Aparticle moves along the x axis. it is initially at the position 0.250 m, moving with velocity 0.050 m/s and acceleration -0.240 m/s2. suppose it moves with constant acceleration for 3.70 s. (a) find the position of the particle after this time. m (b) find its velocity at the end of this time interval. m/s

(a) -1.208 m

The position of the particle at time t is given by

where:

is the initial position

is the initial velocity

is the acceleration

Substituting into the equation t=3.70 s, we find the position after 3.70 seconds:

(b) -0.838 m/s

The velocity of the particle at time t is given by:

where

is the initial velocity

is the acceleration

Substituting t = 3.70 s, we find the velocity after 3.70 seconds:

0.11 m/s and 0.28 m/s should be correct