A73 kg wagon is being pulled by a 210 newton force that is 25 degrees above horizontal on the right. the coefficient of friction on this wagon is 0.23. *there is no net force in the y direction, watch your fn. what is the acceleration?

Acceleration of a wagon is

Explanation:  

From the given question,

Coefficient of friction (µ) = 0.23

Mass of the wagon (m) = 73kg

We know that

Force of friction = µN

µ is coefficient of friction which are given 0.23  

N is the normal reaction

Weight (w) = mg. (Applies at all times even when the object is not accelerated)

g on the earth surface = , substitute the mass and acceleration due to gravity of the earth to obtain Weight.

W = 715.4N

We came to know that the wagon is not moving on vertical direction and no net force in Y direction hence this follows:  

Force = 210 N

88.74 + N = 715

N = 715 - 88.74

N = 626.26

Force of friction = µN  

Force of friction =

Force of friction = 144.04N  

To find the acceleration of a wagon. We know that F = ma

Therefore acceleration of a wagon is .

muscle endurance

explanation:

i can do 50 in a row ( but i get so tired after that)

0.11 m/s and 0.28 m/s should be correct