An astronaut standing on a platform on the moon drops a hammer. if the hammer falls 6.0 meters vertically in 2.7 seconds, what is its acceleration?

The acceleration of the hammer on the moon is 1.65 m/s²

The given parameters;

The acceleration of the hammer is calculated by applying the second equation of motion;

h = ut + ¹/₂at²

where;

6 = 0 + (0.5 x 2.7²) a

6 = 3.645a

Thus, the acceleration of the hammer on the moon is 1.65 m/s²

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the components of a vector are the parts of the vectors that are to each other.

b perpendicular