Aluxury liner has a diesel-electric powerplant with a maximum power of 83 mw at a cruising speed of 39.4 knots. what forward force is exerted on the ship at this speed?

4.09 MN

Explanation:

P(max) = 83 MW

Speed = 39.4 knots

1 knot = 1.852 km/h

Speed in km/h = 39.4 * 1.852

= 72.9688 km/h

= (72.9688*1000) / 3600

= 20.27 m/s

The exerted force is F

P = Fv

P = |F| |v| cos α

P = |F| * 20.27cos 0

P = 20.27F

F = (83 *10^6)/20.27

F = 4.09 * 10^6

F = 4.09MN

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

dang that balls went far